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The rate constant for forward and backwa...

The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2)` and `1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is

A

`4.33`

B

`5.33`

C

`6.33`

D

`7.33`

Text Solution

Verified by Experts

The correct Answer is:
D
Equilibrium constant `K=k_(f)/(k_b)`
`=("Forward rate constant")/("Backward rate constant")`
`K=(1.1xx10^(-2))/(1.5xx10^(-3 ))=(1.1xx10)/(1.5)=(11)/(15)=7.33`
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