The enthalpy of fusion of water is`1.435kcal//mol`.The molar entropy change for the melting of ice at`0^(@)C`is

Options

A. 10.52 cal/mol K
B. 21.04 cal/mol K
C. 5.260 cal/mol K
D. 0.526 cal/mol K

Answer

C

Explanation

Molar entropy change for the melting ice,
`DeltaS_("melt")=(DeltaH_("fussion"))/(T)=(1.435 kcal//"mol")/((0+273)K)`
`=526 xx 10^(-3)` kcal/mol K
=526 cal/mol K