Enthalpy change for the reaction
`2H(2)(g)rarr4H(g)` is `-869.6kJ`
The dissociation energy of `H--H`bond is:

Options

A. `-869.9 KJ`
B. `+434.8 KJ`
C. `+217.4 KJ`
D. `-434.8` KJ

Answer

B

Explanation

`4H(g) to 2H_(2)(g), DeltaH=-869.6 KJ`
`2H_(2)(g) to 4H(g), DeltaH=869.6 KJ`
`H_(2)(g) to 2H(g)`
Dissociation energy of H-H bond
`=(869.6)/(2)=434.8 KJ `