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The enthalpy and entropy change for the ...

The enthalpy and entropy change for the reaction,
`Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)`
are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temperature at which the raction will be in equilibrium is:

A

285.7 K

B

273 K

C

450 K

D

300 K

Text Solution

Verified by Experts

The correct Answer is:
A
At equilibrium Gibbs free energy change `(DeltaG)` is equal to zero.
`DeltaG=DeltaH-TDeltaS`
`0=30xx10^(3) (J "mol"^(-1))-Txx105 (J K^(-1) "mol"^(-1))`
`therefore T=(30xx10^(3))/(105)K=285.71 K `
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