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Change in enthalpy for reaction 2H(2)O(2...

Change in enthalpy for reaction `2H_(2)O_(2)(l)rarr2H_(2)O(l)+O_(2)(g)`
if heat of formation of `H_(2)O_(2)(l)` and `H_(2)O(l)` are `-188` and `-286KJ//mol` respectively is

A

`-196` KJ/mol

B

`+196` KJ/mol

C

`+948` KJ/mol

D

`-948` KJ/mol

Text Solution

Verified by Experts

The correct Answer is:
A
`2H_(2)O_(2)(l) to 2H_(2)O(l) + O_(2)(g) DeltaH=?`
`DeltaH=[(2xxDeltaH_(f) " of " H_(2)O(l) )+ (DeltaH_(f) " of " O_(2)(g)]-(2xxDeltaH_(f) " of " H_(2)O_(2)(l))]`
`=[(12xx-286)+ (0) -(2xx-188)]`
`[-572 + 376 ]=-196` KJ/mol
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