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In frenudlich adsorption isotherm, the v...

In frenudlich adsorption isotherm, the value of `1//n` is

A

between 0 and 1 in all cases

B

between 2 and 4 in all cases

C

1 in cases of physical adsorption

D

1 in case of chemisorption

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The correct Answer is:
A

In Freundlich adsorption isotherm,
`(x)/(m)= kp^(1//n)`
Where, x = amount of adsorbent
m = amount of adsorbate
The value of n is always greater than 1. So, the value of 1/n lies between 0 and 1 in all cases.
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Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) In the mathematical relation of Freundlich adsorption isotherm ,the value of (1/n) is 0 le (1)/(n) le 1 . (a) True (b) False

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