Pick out the correct statement with respect to `[Mn(CN)_(6)]^(3-)`:

Options

A. It is `sp^(3)d^(2)` hybridised and octahedral
B. It is `sp^(3)d^(2)` hybridised and tetrahedral
C. It is `d^(2)sp^(3)` hybridised and octahedral
D. It is `dsp^(2)` hybridised and square planar

Answer

C

Explanation

`[Mn(CN)_(6)]^(3-)` is `d^(2)sp^(3)`- hybridised and octahedral complex. In `[Mn(CN)_(6)]^(3-)`, Mn is in +3 oxidation state
`Mn^(3+)=3d^(4)4s^(0)`