The hybridization involved in complex `[Ni(CN)_(4)]^(2-)` is `(At. No . Ni = 28)`

Options

A. `dsp^(3)`
B. `sp^(3)`
C. `d^(2)sp^(2)`
D. `d^(2)sp^(3)`

Answer

A

Explanation

`[Ni(CN)_4 ]^(2 -)`
Let oxidation state of Ni in `[Ni(CN)_4 ]^(2 -)` is x
`therefore x-4 = -2`
or x= 2
Now, `Ni^(2+) = [Ar] 3d^8 4s^0`

`therefore CN^-`is a strong field ligand. Hence, all unpaired electrons are paired up.

`therefore " Hybridisation of " [Ni(CN)_4 ]^(2 -) is dsp^(2)`