Crystal field stabilization energy for high spin `d^4` octahedral complex is

Options

A. `-1.8Delta_(0)`
B. `-1.6Delta_(0)+P`
C. `-1.2Delta_(0)`
D. `-0.6Delta_(0)`

Answer

D

Explanation

(d) Key Idea In case of high spin complex, `Delta_(o)` is small. Than the pairing energy. That means, the energy required to pair up the fourth electorn with the electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital Thus, painng does not occur. For high spin `d^(4)` octahedral complex.

`therefore` Crystal field stabilisation energy
`=(-3xx0.4+1xx0.6)Delta_(o)`
`=(-1.2+0.6)Delta_(o)=-0.6Delta_(o)`