A coordination compound of cobalt has the molecular, formula containing five ammonia molecules, one nitro group and two chlorine atoms for onew cobalt atom. One mole of this compounds three ions in an aqueous solution. On reacting this solution with excess of `AgNO_(3)` solution, we get two moles of AgCI precipitate. The ionic formula for this complex would be

Options

A. `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)`
B. `[Co(NH_(3))_(5)Cl][Cl(NO_(2))]`
C. `[Co(NH_(3))_(4)(NO_(2))Cl][(NH_(3))Cl]`
D. `[Co(NH_(3))_(5)][(NO_(2))_(2)Cl_(2)]`

Answer

A

Explanation

The complex gives three ions in aqueous solution.
`therefore" The complex should be "[Co(NH_(3))_(5)NO_(2)]^(2+)`.
It will give three ions on dissociation as follows :
`[Co(NH_(3))_(5)NO_(2)]Cl_(2)rarrunderset("1 mol")([Co(NH_(3))_(5)NO_(2)]^(2+))+underset("2 mol")(2Cl^(-))("Counter ion")`
`2Cl^(-)+2AgNO_(3)rarrunderset("Silver ppt")(2AgCl)+2NO_(3)^(-)`