" 17."(dy)/(dx)=y sec x;" enc "y=1," यरन "x=(pi)/(6)" रु(४। "

(dy)/(dx)+y sec x=tan x

(dy)/(dx)+y tan x=sec x

1-(dy)/(dx)=sec(x-y)," where "x-y=u

2 (dy) / (dx) -y sec x = y ^ (3) tan x

if y(x) is satisfy the differential equation (dy)/(dx)=(tan x-y)sec^(2)x and y(0)=0. Then y=(-(pi)/(4)) is equal to

(dy)/(dx)+(y)/(2)sec x=(tan x)/(2y)

Solve: (dy)/(dx)=(1)/(x cot y+sec y)

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve (dy)/(dx)+y tan x=y^(2)sec x

Solve (dy)/(dx)+y tan x=y^(2)sec x