Through the centriod of an equilateral triangle a line parallel to the base is drawn. On this line, an arbitary point P is taken inside the triangle. Let h denote the distahce of P from the base of the triangle. Let `h_(1) and h_(2)` be the distance of P from the other two sides of the triangle, then

Through the centroid of an equilateral triangle, a line parallel to the base is drawn. On this line, an arbitrary point P is taken inside the triangle. Let h denote the perpendicular distance of P from the base of the triangle. Let h_(1) and h_(2) be the perpendicular distance of P from the other two sides of the triangle . Then :

Through the centroid of an equilateral triangle, a line parallel to the base is drawn. On this line, an arbitrary point P is taken inside the triangle. Let h denote the perpendicular distance of P from the base of the triangle. Let h_(1) and h_(2) be the perpendicular distance of P from the other two sides of the triangle . Then :

Through the centroid of an equilateral triangle, A line parallel to the base is drawn. On this line an arbitrary point P is taken inside the triangle. Let h denote the bot^("lar") distance of P from the base, h_1 h_2 are bot^("lar") distances from other two sides then

A point P is inside an equilateral triangle. If the distances of P from sides 8, 10, 12 then length of the side of the triangle is

A point P is inside an equilateral triangle if the distance of P from sides 8,10,12 then the length of the side of the triangle is

If the base of an isosceles triangle is of length 2a and the length of altitude dropped to the base is h then the distance from the midpoint of the base to the side of the triangle is

If the base of an isosceles triangle is of length 2P and the length of the altitude dropped to the base is q, then the distance from the mid point of the base to the side of the triangle is

Prove that a line drawn from the vertex of a triangle to its base is bisected by the line joining the mid points of the remaining two sides of the triangle.