Calculate the grams of copper sulphate `(CuSO_(4))` needed to prepare `250.0 mL` of `1.00M CuSO_(4)` ?.

Explanation

Moles of `CuSO_(4) = M xx V = 1 xx (250)/(1000)`
Molar mass of copper sulphate = 159.6 g/mol
Hence Mass of copper sulphate (gm) = Moles of `CuSO_(4) xx` Molar mass of copper sulphate
`= 1 xx (250)/(1000) xx 159.6 g//mol`
= 39.9 gm of Copper sulphate