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Find final molarity in each case :...

Find final molarity in each case :

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(i) `500 ml 0.1 M HCl + 500 ml 0.2 M HCl`
`M_(f) = (500 xx 0.1 + 500 xx 02)/(500 + 500) = 0.15 M`
(ii) `50 ml 0.1 M HCl + 150 " " 0.3 M HCk + 300 ml H_(2)O`
`M_(f) = (50 xx 0.1 + 150 xx 0.3)/(50 + 150 + 300) = (50)/(500) = 0.1 M`
(iii) `4.9 g H_(2)SO_(4) + 250 ml H_(2)O + 250 ml 0.1 M H_(2)SO_(4)`
`M_(f) = ((4.9)/(98) + (250)/(1000) xx 0.1)/(((250 + 250)/(1000))) = (50 + 25)/(500) = 0.15 M`
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