What volume of `1M` & `2M H_(2)SO_(4)` solution are required to produce `2L` of `1.75M H_(2)SO_(4)` solution ? .

Explanation

Let XL be vol. of 1M solution.
`:. (2 - X)L` is vol. of 2M solution
Moles of `H_(2)SO_(4) = 2 xx 1.75 = 1 (X) + (2 - X) 2`
`3.5 = 4 - X , X = 0.5 L`
i.e., 0.5 L of 1 M & 1.5 L of 2M solution requires