Home
Class 12
CHEMISTRY
6.02 xx 10^(21) molecules of urea are pr...

`6.02 xx 10^(21)` molecules of urea are present in 100ml of its solution. The concentration of urea solution is

A

`0.001 M`

B

`0.01 M`

C

`0.02 M`

D

`0.1 M`

Text Solution

Verified by Experts

The correct Answer is:
D
Moles of urea `= (6.02 xx 10^(21))/(6.02 xx 10^(23)) = (1)/(100)`
Molarity `= (1000)/(100 xx 100) = 0.1 M`
Promotional Banner

Topper's Solved these Questions

  • CONCENTRATION TERMS

    ALLEN|Exercise Basic Exercise|14 Videos

  • CONCENTRATION TERMS

    ALLEN|Exercise Exercise S - I|30 Videos

  • CONCENTRATION TERMS

    ALLEN|Exercise Exercise Jee-Advance|3 Videos

  • ACIDIC STRENGTH & BASIC STRENGTH

    ALLEN|Exercise Exercise V|16 Videos

Similar Questions

Explore conceptually related problems

6.02xx10^(23) molecules of urea are present in 100 ml of its solution. The concentration of urea solution is -

6.02 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is (Avogadro constant, N_(A) = 6.02 xx 10^(23)mol^(-1))

6.02xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of solution is :