Calculate molarity of all the ions produces by following aq. Solution of electrolytes. (Assuming 100% dissociation)
(i) 0.2 M NaCl solution
(ii) 1.2 M `Al_(2)(SO_(4))` solution
(iii) 1.2 M `H_(2)SO_(4)` solution
(vi) 2.1 M `MgCl_(2)` solution

Answer

(i) `|{:(NaCl,rarr,Na^(+),+,Cl^(-)),(0.2,,0.2,,0.2):}|`
(ii) `|{:(H_(2)SO_(4),rarr,2H^(+),+,SO_(4)^(-2)),(0.05,,0.1,,0.05):}|`
(iii) `|{:(Al_(2)(SO_(4)),rarr,2Al^(3+),+,3SO_(4)^(-2)),(1.2,,2.4,,3.6):}|`
(iv) `|{:(MgCl_(2),rarr,"Mg"^(2+),+,2Cl^(-)),(2.1,,2.1,,4.2):}|`