20 ml of '20 vol' H(2)O(2) solution is d...

20 ml of '20 vol' `H_(2)O_(2)` solution is diluted to 80 ml. The final volume strength of solution is

80 vol'

25 vol'

5 vol'

8 vol'

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50 ml of '20 V' H_(2)O_(2) is mixed with 200 ml, '10 V' H_(2)O_(2). The volume strength of resulting solution is:

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To a 25 mL of H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3 N Na_(2)S_(2)O_(3) solution. Calculate the volume strength of H_(2)O_2 solution. Strategy : Volume strength of H_(2)O_(2) solution is related to its normality by the following relation Volume strength (V)=5.6xx"Normality" (N) where, Normality =((meq)H_(2)O_(2))/V_(mL) According to the law of equivalence (meq)_(Na_(2)S_(2)O_(3))=(meq)_(I_(2))=(meq)_(H_(2)O_(2))

40 ml of 22.7 V H_(2)O_(2) solution is mixed with 60 ml of 8.5% (w//v) H_(2)O_(2) solution and the mixture is diluted to 230 ml. If 20 ml of diluted solution is callected in an empty beaker, the molarity of collected solution is:

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ALLEN- CONCENTRATION TERMS-Exercise O-I

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