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31 gm H(2)SO(4) is mixed with 20 gram SO...

31 gm `H_(2)SO_(4)` is mixed with 20 gram `SO_(3)` to form mixture
Determine % labelling of oleum solution

A

`104.5`

B

106

C

109

D

110

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The correct Answer is:
C
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30 gm H_(2)SO_(4) is mixed with 20 gram SO_(3) to form mixture Find mole fraction of SO_(3)

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Oleum is considered as a solution of SO_(3) in H_(2)SO_(4) , which is obtained by passing SO_(3) in solution of H_(2)SO_(4) When 100 g sample of oleum is diluted with desired mass of H_(2)O then the total mass of H_(2)SO_(4) obtained after dilution is known is known as % labelling in oleum. For example, a oleum bottle labelled as ' 019% H_(2)SO_(4) ' means the 109 g total mass of pure H_(2)SO_(4) will be formed when 100 g of oleum is diluted by 9 g of H_(2)O which combines with all the free SO_(3) present in oleum to form H_(2)SO_(4) as SO_(3)+H_(2)O to H_(2)SO_(4) What is the % of free SO_(3) in an oleum that is labelled as '104.5% H_(2)SO_(4)' ?

Oleum is considered as a solution of SO_(3) in H_(2)SO_(4) , which is obtained by passing SO_(3) in solution of H_(2)SO_(4) When 100 g sample of oleum is diluted with desired mass of H_(2)O then the total mass of H_(2)SO_(4) obtained after dilution is known is known as % labelling in oleum. For example, a oleum bottle labelled as ' 019% H_(2)SO_(4) ' means the 109 g total mass of pure H_(2)SO_(4) will be formed when 100 g of oleum is diluted by 9 g of H_(2)O which combines with all the free SO_(3) present in oleum to form H_(2)SO_(4) as SO_(3)+H_(2)O to H_(2)SO_(4) 1 g of oleum sample is diluted with water. The solution required 54 mL of 0.4 N NaOH for complete neutralization. The % free SO_(3) in the sample is :

(i) 2 gm H_(2)SO_(4) is dissolved in 38 gm water. Find (w/w)%

10 gm NaOH and 9.8 gm H_(2)SO_(4) are allowed to react by which 8.52 gm Na_(2)SO_(4) is formed. The percentage yield of products is -

200 gm of an oelum sample (labelled as 109 % ) is mixed with 400 gm of another oleum sample (labelled as 118 % ). The labelling of the new sample formed will be :

ALLEN- CONCENTRATION TERMS-Exercise O-II
  1. Statement-1 : 0.5 M aq. NaOH solution is identical to 2% (w/v) aq. NaO...

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  2. The molar concentration of HCl (aq.) is 10^(-5)M. Which of the followi...

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  3. Solution (s) containing 40 gm NaOH is/are

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  4. The incorrect statement (s) regarding 2M MhCl(2) aqueous solution is/a...

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  5. A sample of H(2)O(2) solution labelled as 56.75 volume has density of ...

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  6. 100 ml "of" 0.06 M Ca (NO(3))(2) is added to 50 mL of 0.06 M Na(2)C(2)...

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  7. 2 litre of 9.8% w/w H(2)SO(4) (d = 1.5 gm/ml) solution is mixed with 3...

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  8. If 2 litre of 9.8% w//w H(2)SO(4) (d = 1.5 g//mL) solution is mixed wi...

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  9. 30 gm H(2)SO(4) is mixed with 20 gram SO(3) to form mixture Find mol...

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  10. 31 gm H(2)SO(4) is mixed with 20 gram SO(3) to form mixture Determin...

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  11. Estimation of nitrogen: There are two methods for the estimation of ni...

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  12. Estimation of nitrogen: There are two methods for the estimation of ni...

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  13. Estimation of nitrogen: There are two methods for the estimation of ni...

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  14. Estimation of nitrogen: There are two methods for the estimation of ni...

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  15. Which of the following is correct match ?

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  16. Which of the following is correct match?

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  17. Which of the following is correct match ?

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  18. Match the column

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  19. Match the column

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  20. Text Solution

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