The volume strength of `1M H_(2)O_(2)` is (Molar mass of `H_(2)O_(2) = 34 g mol^(-1)`)

Options

A. 16.8
B. 11.35
C. 22.4
D. 5.6

Answer

To find the volume strength of 1M H₂O₂, we need to understand the concept of volume strength and how it relates to the decomposition of hydrogen peroxide (H₂O₂).

### Step-by-Step Solution:

1. **Understand Volume Strength**:
Volume strength is defined as the volume of oxygen gas (O₂) released when 1 liter of the solution decomposes completely. For hydrogen peroxide, the decomposition reaction is:
\[ 2H_2O_2 \rightarrow 2H_2O + O_2 \]
This means that 2 moles of H₂O₂ produce 1 mole of O₂.

2. **Calculate Moles of H₂O₂ in 1L of 1M Solution**:
Since the concentration is 1M, in 1 liter of this solution, there is 1 mole of H₂O₂.

3. **Determine Moles of O₂ Produced**:
From the balanced equation, 2 moles of H₂O₂ produce 1 mole of O₂. Therefore, 1 mole of H₂O₂ will produce:
\[ \text{Moles of O}_2 = \frac{1 \text{ mole H}_2O_2}{2} = 0.5 \text{ moles O}_2 \]

4. **Convert Moles of O₂ to Volume at STP**:
At standard temperature and pressure (STP), 1 mole of gas occupies 22.4 liters. Therefore, the volume of 0.5 moles of O₂ is:
\[ \text{Volume of O}_2 = 0.5 \text{ moles} \times 22.4 \text{ L/mole} = 11.2 \text{ L} \]

5. **Conclusion**:
Hence, the volume strength of 1M H₂O₂ is 11.2.

### Final Answer:
The volume strength of 1M H₂O₂ is **11.2**.