Home
Class 12
CHEMISTRY
50 gm of CaCO(3) is allowed to react wit...

50 gm of `CaCO_(3)` is allowed to react with 68.6 gm of `H_(2)PO_(4)` then select the correct option(s)-
`3CaCO_(3)+ 2H_(3)PO_(4) to Ca_(3)(PO_(4))_(2) + 3H_(2)O + 3CO_(2)`

A

51.67 gm salt is formed

B

Amount of unreacted reagent =35.93 gm

C

`n_(CO_(2))`=0.5 moles

D

0.7 moles `CO_(2)` is evolved

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise O-II (Match the column:)|3 Videos

  • MOLE CONCEPT

    ALLEN|Exercise J-MAINS|16 Videos

  • MOLE CONCEPT

    ALLEN|Exercise O-II (Assertion Reason:)|2 Videos

  • METALLURGY

    ALLEN|Exercise EXERCISE-05 [B]|26 Videos

  • p-Block Element

    ALLEN|Exercise All Questions|20 Videos

Similar Questions

Explore conceptually related problems

50 gm of CaCO_(3) is allowed to react with 68.6 gm of H_(3)PO_(4) then select the correct option(s): 3CaCO_(3) +2H_(3)PO_(4) rarr Ca_(3)(PO_(4))_(2)+3H_(2)O+3CO_(2)

Ca_(3)(PO_(4))_(2) +H_(2)SO_(4) to

H_(3)PO_(2)+CuSO_(4) to Cu darr+H_(3)PO_(4)+HNO_(3)

Find out the equivalent weight of H_(3) PO_(4) in the reaction: Ca(OH)_(2) + H_(3) PO_(4) rarr CaHPO_(4) + 2 H_(2) O

50 g of CaCO_(3) is allowed to react with 70 g of H_(3)PO_(4^(.) Calculate : (i) amount of Ca_(3)(PO_(4))_(2) formed (ii) amount of unreacted reagent

The Ew of H_(3) PO_(4) in reaction is Ca(OH)_(2) + H_(3) PO_(4) rarr CaHPO_(4) + 2H_(2)O (Ca = 40, P = 31, O = 16)