Equilibrium constant `K_(p)` for
`H_(2)S(g) hArr 2H_(2)(g)+S_(2)(g)`
is `0.0118` atm at `1065^(@)C` and heat of dissociation is `42.4` Kcal. Find equilibrium constant at `1132^(@)C`.

Equilibrium constant (K_(p)) for 2H_(2)S_((g))hArr2H_(2(g))+S_(2(g)) is 0.0118 atm at 1065^(@)C and heat of dissociation is 42.4 kcal . Find equilibrium constant at 1132^(@)C .

The equilibrium constant for, 2H_2S(g) iff 2H_2(g) + S_2(g) is 0.469 atm at 1065^@C and heat of dissociation is 42.4 kcalmol^-1 . Calculate the equilibrium constant at 1132^@C .

The equilibrium constant for, 2H_(2)S (g)hArr 2H_(2)(g) + S_(2)(g) is 0.0118 at 1300 K while the heat of dissociation is 597.4 kJ. The standard equilibrium constant of the reaction at 1200 K is

The equilibrium constant for, 2H_(2)S(g)hArr2H_(2)(g)+S_(2)(g) "is" 0.0118 "at" 1300 K while the heat of dissociation is 597.4KJ . The standard equilibrium constant of the reaction at 1200K is:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if: