If `x=3-sqrt8," then find the value of "1/sqrtx-sqrtx`.

If x = 1 + sqrt2 , then find the value of sqrtx+(1/sqrtx) . यदि x = 1 + sqrt2 , है, तो sqrtx+(1/sqrtx) का मान ज्ञात कीजिए ?

If x=3+2 sqrt2 , then the value of sqrtx-1/sqrtx is : यदि x=3+2 sqrt2 , तब sqrtx-1/sqrtx का मान :

If x = 2 + sqrt3 then the value of sqrtx + 1/sqrtx is

If x = 3 + 2 sqrt2 , find the value sqrtx - (1)/(sqrtx)

If x = 5+2sqrt6 , then the value of (sqrtx +frac(1)(sqrtx)) is (A) 2sqrt2 (B) 3sqrt2 (C ) 2sqrt3 (D) 3sqrt3