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The expression (sin 8thetacos theta-sin6...

The expression `(sin 8thetacos theta-sin6 thetacos 3 theta)/(cos 2 thetacos theta-sin 3 thetasin 4 theta)` is equals:-

A

`tan theta`

B

`tan 2 theta`

C

`sin 2 theta`

D

`cos 2 theta`

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The correct Answer is:
B
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