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If tanB= (nsinA cosA)/(1-ncos^2A)then ...

If `tanB= (nsinA cosA)/(1-ncos^2A)`then `tan(A +B)` equals

A

`(sinA)/(1-ncosA)`

B

`((n-1)cosA)/(sinA)`

C

`(SinA)/((n-1)cos A)`

D

`(sinA)/((n+1)cosA)`

Text Solution

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The correct Answer is:
B
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