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A stone tied at the end of a string 80 c...

A stone tied at the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 25 revolutions in 14 s, what is the magnitude of acceleration of the stone ?

Text Solution

Verified by Experts

The correct Answer is:
`9.9 ms^(-2)`, in radial direction towards the centre at all points.
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A stone tied to the end of string 80 cm long is whirled in horizontal circle with a constant speed. If the stone makes 14 revolution in 25 sec, what is the magnitude of acceleration of the stone?

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Knowledge Check

  • A stone is tied to one end of a string 50 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 10 revolutions in 20 s , what is the magnitude of acceleration of the stone

    A
    `493 cm//s`
    B
    `720 cm//s`
    C
    `860 cm//s`
    D
    `990 cm//s`

  • A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, the magnitude of acceleration is :

    A
    `20 ms^(-2)`
    B
    `12 m//s^(-2)`
    C
    `9.9 ms^(-2)`
    D
    `8 ms^(-2)`

  • A stone tied to a string of 80 cm long is whireled in a horizontal circle with a constant speed. If the stone makes 25 revolutions in 14 s then, magnitude of acceleration of the same will be:

    A
    `990 cm//s^(2)`
    B
    `680 cm//s^(2)`
    C
    `750 cm//s^(2)`
    D
    `650 cm//s^(2)`

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