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For a particle in uniform circular motio...

For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

A

`(v^(2))/(R)hati+(v^(2))/(R)jhat`

B

`-(v^(2))/(R)cos thetahati+(v^(2))/(R)sin thetajhat`

C

`-(v^(2))/(R)sin thetahati+(v^(2))/(R)cos thetajhat`

D

`-(v^(2))/(R)cos thetahati-(v^(2))/(R)sin thetajhat`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • For a particle in uniform circular motion the acceleration vec a at a point P ( R, theta ) on the circle of radius R is : ( here theta is measured from the x- axis )

    A
    ` - (v^ 2 )/(R ) cos theta hati + (v^2 ) /(R ) sin theta hatj `
    B
    ` - ( v ^ 2 ) /( R ) sin theta hati + (v ^ 2 )/( R ) cos theta hatj `
    C
    ` - (v ^ 2 )/( R ) cos theta hai - (v ^ 2 ) / ( R ) sin theta hatj `
    D
    ` (v^ 2 )/ (R ) hati + (v ^ 2 ) /( R ) hatj `

  • For a particle performing a uniform circular motion the acceleration is

    A
    constant in direction
    B
    constant in magnitude but not in direction
    C
    constant in magnitude and direction
    D
    constant neither in magnitude nor in direction.

  • In a non uniform circular motion, the acceleration on the particle is

    A
    centripetal acceleration only
    B
    tangential acceleration only
    C
    the resultant centripetal and tangential acceleration
    D
    centrifugal acceleration

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