" 3.If "s=ut+(1)/(2)" at "^(2)" ,where "u" and a are constants.Obtain the value of "(ds)/(dt)

Given S=ut+1/2at^2 ,where u and a are constant , obtain the value of ds/dt

If s = at^(2) + bt + c find the value of [(ds)/(dt)]_(t=1) .

In S=ut+(1)/(2)at^(2) , S=96,t=8 and a=2 , find u.

If (dT)/dt=-K(T-S) where K and S are constants,find T when T(0)=100.

Integrate the following : int_(3)^(6)(u+at)dt where u and a are constants.

In s=ut+(1)/(2)at^(2) , if s=16m,t=2 seconds and a=5m//s^(2) , then find the value of u by making u as the subject.

The maximum height is reached is 5s by a stone thrown vertically upwards and moving under the equation 10s=10ut-49t^(2) , where s is in metre and t is in second. The value of u is

Check the accuracy of the relation s = ut + (1)/(2)at^(2) where s is the distance travelled by the with uniform acceleration a in time t and having initial velocity u.