" (a) "r=3cm^((1)/(6))

Find the rate of change of the area of a circle with respect to its radius r when (a) r=3cm (b) r=4cm

A sector of 56o has an area of 17.6cm2. Then its radius will be (a) 1.5cm(b)3cm(c)4.2cm (d) 6cm

In Figure, R Q is a tangent to the circle with centre O . If S Q=6c m and Q R=4c m , then O R= (a) 8cm (b) 3cm (c) 2.5cm (d) 5cm

In Fig. 10.79, R Q is a tangent to the circle with centre O . If S Q=6c m and Q R=4c m , then O R= (FIGURE) (a) 8cm (b) 3cm (c) 2.5cm (d) 5cm

In r_(1)=(A)/(s-a) , if A=12cm^(2),r_(1)=4cm and a=3cm then find s making s as the subject.

The value of sum_(r=0)^(3n-1)(-1)^(r)6nC_(2r+1)3^(r) is

The value of sum_(r=0)^(3n-1)(-1)^r 6nC_(2r+1)3^r is

There are three relations R_(1) , R_(2) and R_(3) such that R_(1) = {(2,1),(3,1),(4,2)} , R_(2) = {(2,2),(2,4),(3,3),(4,4)} and R_(3) = {(1,2),(2,3),(3,4),(4,5),(5,6),(6,7)} then

The length of x of a rectangle is decreasing at the rate of 3cms^(-1) and the widty y is increasing at the rate of 3cms^(-1) when x=10cm and y=6cm then the rate of change of the area of rectangle is