[" In an LC circuit the capacitor has maximum "],[" charges "q_(0)." The value of "((dI)/(dt))_(max)" is :- "]

In an LC circuit the capacitor has maximum charge q_0 . The value of ((dI)/(dt))_(max) is

In an LC circuit the capacitor has maximum charge q_0 . The value of ((dI)/(dt))_(max) is

In LC circuit the maximum charge in capacitor is q_0 . Then maximum value of rate of change of current is

In LC circuit the maximum charge in capacitor is q_0 . Then maximum value of rate of change of current is

An LCR circuit is equivalent to a damped pendulam. In an LCR circuit the capacitor is charged to Q_0 and then connected to the L and R as shown below: If the students plots graphs of the square of maximum charge (Q_(max)^2) on the capacitor with time (t) for two different values L_1 and L_2(L_1gtL_2) of L then which of the following represents this graph correctly?(plots are schematice are not drawn to scale)

An LCR circuit is equivalent to a damped pendulum. In an LCR circuit the capacitor is charged to Q_0 and then connected to the L and R as shown below: If a student plots graphs of the square of maximum charge (Q_"Max"^2) on the capacitor with time (t) for two different values L_1 and L_2 (L_1 gt L_2) of L then which of the following represents this graph correctly ? (plots are schematic and not drawn to scale)

An LC circuit oscillating at natural frequency conssts of an inductor of inductance 30 m H and a capacitor of capacitance 60 muF . The maximum value of instantaneous charge on capacitor in the circuit is 250 mu C . If I is the current in the circuit then answer the following : (i) What is the value of (dI)/(dt) when charge is 150 mu C? (ii) Calculate the value of I when charge is 200 muC . (iii) Find the maximum value of I. (iv) For what value of q I is half of its maximum value ?

Assertion : Angular frequency of LC oscillations is 2 rad//s and maximum current in the circuit is 1 A . Then, maximum rate of change of current should be 2 A//s . Reason: ((dI)/(dt))_(max)=(I_(max))omega