Home
Class 12
MATHS
A person observes the angle of elevation...

A person observes the angle of elevation of the peak of a hill from a station to be `alpha`. He walks c metres along a slope inclined at the angle `beta` and finds the angle of elevation of the peak of the hill to be `gamma`.Show that the height of the peak above the ground is `(c sinalphasin(gamma-beta))/(sin(gamma-alpha))`

Promotional Banner

Similar Questions

Explore conceptually related problems

A person observes the angle of elevation of the peak of a hill from a station to be alpha. He walks c metres along a slope inclined at the angle beta and finds the angle of elevation of the peak of the hill to be gamma. Show that the height of the peak above the ground is (c sin alpha sin(gamma-beta))/(sin(gamma-alpha))

The angle of elevation of the top of a hill from a point is alpha . After walking b metres towards the top up of a slope inclined at an angle beta to the horizon, the angle of elevation of the top becomes gamma . Then , the height of the hill is

The angle of elevation of the top of a hill from a point is alpha . After walking b metres towards the top up a slope inclined at an angle beta to the horizontal,the angle of elevation of the top becomes gamma .Then the height of the hill is :

From a point a metres above a lake the angle of elevation of a cloud is alpha and the angle of depression of its reflection is beta . Prove tha the height of the cloud is (a sin(alpha + beta))/(sin(beta-alpha)) metres.

The angle of elevation of the top of a hill is 30^(@) from a point on the ground. On walking 1 km towards the hill, angle is found to be 45^(@) . Calculate the height of the hill.

The angle of elevation of an object on a hill from a point on the ground is 30^@ . After walking 120 metres the elevation of the object is 60^@ . The height of the hill is

The angle of elevation of an object on a hill from a point on the ground is 30^@ . After walking 120 metres the elevation of the object is 60^@ . The height of the hill is