a^(4)*sa^(2)+36

a^(4)-5a^(2)+36

e is the eccentricity of the ellipse 4x^(2)+9y^(2)=36 and C is the centre and S is the focus and A is the vertex then CS:SA=

Factorise : 4x^(4) - x^(2) - 12x - 36

If rlt0 and (4r-4)^(2)=36 , what is the value of r?

If a^(2) - b^(2) = 36 and a + b = 4 then (a - b)^(2) = "______" .

If a+b+c=6,a^(2)+b^(2)+c^(2)=14sa^(3)+b^(3)+c^(3)=36, find abc.

S and S' are the foci and A is one vertex of x^(2)-2y^(2)=1 then SA.S A=

((63+36)^(2)+(63-36)^(2))/(63^(2)+36^(2)) =?

Factorise the following 4x^(2) - 36

(36^((7)/(2))-36^((9)/(2)))/(36^((5)/(2)))