Propene is allowed to react with `B_(2)D_(6)` and the product is treated with acetic acid. The final product obtained is -

Options

A. `1-`deuteriopropane
B. `2-`deuteriopropane
C. `1-`deuteriopropene
D. `2-`deuteriopropene

Answer

To solve the problem of what product is obtained when propene reacts with B2D6 and is subsequently treated with acetic acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants are propene (C3H6) and B2D6 (diborane with deuterium).

2. **Understand Hydroboration-Oxidation**: The reaction of propene with B2D6 involves hydroboration-oxidation, which follows the anti-Markovnikov's rule. This means that the nucleophilic part (in this case, deuterium) will add to the less substituted carbon atom of the alkene.

3. **Draw the Structure of Propene**: The structure of propene is CH3-CH=CH2. The double bond is between the second and third carbon atoms.

4. **Determine the Addition of Deuterium**: According to the anti-Markovnikov's rule:
- The carbon with more hydrogen (the terminal carbon, CH2) will receive the deuterium (D).
- The other carbon (the one with the double bond) will receive the hydroxyl group (OH) after hydrolysis.

5. **Product after Hydroboration**: After the reaction with B2D6, the product will be:
- CH3-CH(OH)-CH2D (where D is the deuterium)
- This product is 1-deuteropropanol.

6. **React with Acetic Acid**: The next step involves treating the product with acetic acid (CH3COOH). In this case, the hydroxyl group (OH) will react with acetic acid, leading to the formation of an ester.

7. **Formation of the Final Product**: The hydroxyl group will be replaced by the acetic acid group, resulting in:
- CH3-CH(D)-COOCH3 (where D is still the deuterium).
- This compound is 2-deuteropropyl acetate.

### Final Product:
The final product obtained is **2-deuteropropyl acetate**.