The major product obtained in the reaction of `1,3-`Butadiene with `HCl` (`1` mole) at a higher temperature (`100^(@)C` or above ) is

Options

A. `3,4-`dichloro`-1-`butene
B. `3-`chloro`-1-`butene
C. `1-`chloro`-2-`butene
D. `2-`chloro`-2-`butene

Answer

To determine the major product obtained from the reaction of 1,3-butadiene with HCl at a higher temperature (100°C or above), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 1,3-Butadiene**:
- 1,3-butadiene has the formula C4H6 and consists of four carbon atoms with two double bonds. The structure can be represented as:
```
H2C=CH-CH=CH2
```

2. **Understand the Reaction Conditions**:
- The reaction involves the addition of HCl to 1,3-butadiene. Since the reaction is taking place at a higher temperature, we expect to follow the Markovnikov's rule and the formation of a more stable product.

3. **Reaction Mechanism**:
- The reaction of HCl with 1,3-butadiene will proceed through an electrophilic addition mechanism. The double bonds in the conjugated alkene can react with HCl, leading to the formation of a carbocation intermediate.

4. **Formation of Carbocation**:
- When HCl adds to 1,3-butadiene, the hydrogen (H+) will add to one of the terminal carbons, leading to the formation of a more stable secondary carbocation at the second carbon:
```
H2C=CH-CH=CH2 + HCl → H3C-CH(Cl)-CH=CH2
```

5. **Final Product**:
- The chlorine (Cl-) will then attach to the carbon that has fewer hydrogen atoms, following the Markovnikov's rule. This results in the formation of 3-chloro-1-butene:
```
CH2=CH-CH(Cl)-CH3
```

6. **Naming the Product**:
- The product can be named according to IUPAC nomenclature. The chlorine is on the third carbon, and there is a double bond between the first and second carbon. Therefore, the name of the compound is 3-chloro-1-butene.

### Conclusion:
The major product obtained from the reaction of 1,3-butadiene with HCl at a higher temperature is **3-chloro-1-butene**.