The intermediate during the addition of `HCl` to propene in the presence of peroxide is :

Options

A. `CH_(3)CHCH_(4)CL`
B. `CH_(3)overset(o+)CHCH_(3)`
C. `CH_(3)CH_(2)overset(*)CH_(2)`
D. `CH_(3)CH_(2)overset(o+)CH_(2)`

Answer

To determine the intermediate during the addition of HCl to propene in the presence of peroxide, we can follow these steps:

### Step 1: Understand the structure of propene
Propene is an alkene with the molecular formula C3H6. Its structure can be represented as:
```
H H
\ /
C
/ \
H C
|
H
```
This can also be written as CH2=CH-CH3.

### Step 2: Identify the reaction conditions
The reaction involves the addition of HCl (hydrochloric acid) to propene in the presence of peroxide (R2O2). The presence of peroxide indicates that the reaction will proceed via a free radical mechanism, which is different from the typical electrophilic addition.

### Step 3: Determine the mechanism of the reaction
In the presence of peroxide, the addition of HCl to propene follows an anti-Markovnikov rule due to the formation of free radicals. This means that the hydrogen atom will add to the carbon with the least number of hydrogen atoms (the less substituted carbon).

### Step 4: Formation of the free radical
When HCl is added to propene in the presence of peroxide, the first step involves the formation of a free radical. The peroxide initiates the reaction by generating free radicals that react with HCl to form H• (hydrogen radical) and Cl• (chlorine radical).

### Step 5: Addition of the hydrogen radical to propene
The hydrogen radical (H•) will add to the terminal carbon of propene (the carbon with more hydrogen atoms), leading to the formation of a secondary radical:
```
H H
\ /
C• (This is the radical intermediate)
/ \
H C
|
H
```
This secondary radical is more stable than a primary radical.

### Step 6: Final product formation
The chlorine radical (Cl•) will then add to the carbon with the radical, resulting in the final product. The intermediate formed during this reaction is the secondary radical.

### Conclusion
The intermediate during the addition of HCl to propene in the presence of peroxide is a secondary free radical.

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