For the reaction
`CaO+2HCl to CaCl_(2)+H_(2)O`
1.23g of CaO is reacted with excess of nydrochloric acid and 1.85g of `CaCl_(2)` is formed. What is the per cent yeild.

CaCO_(3) + 2HCl to CaCl_(2) + H_(2)O + CO_(2) 0.2 mole CaCO_(3) is reacted with excess of HCl. Find mass of CO_(2) produced?

With the help of the equation CaCO_(3) + 2HCl to CaCl_(2) + H_(2)O + CO_(2) , calculate the following : The mass of CaCl_(2) formed from 10 g CaCO_(3) .

With the help of the equation CaCO_(3) + 2HCl to CaCl_(2) + H_(2)O + CO_(2) , calculate the following : The volume of CO_(2) formed at STP from 10 g CaCO_(3) .

Balance the following equation: CaO+HCl to CaCl_(2)+H_(2)O

Ammonia gas can be prepared by following reaction : CaO (s) + 2NH_(4) Cl (s) rarr 2NH_(3) (g) + H_(2)O (g) + CaCl_(2) (s) If 112 gm of CaO and 224 gm of NH_(4)Cl are mixed and 17 gm of NH_(3) is formed then

10 g of S reacts with excess of O_2 to form 15 g of SO_2. The % yield of the reaction is