[" Mimi mine "z=20x+10y],[" dubject "(1)/(a)1.5s+3y leqslant42,3x+y]

Maximize Z=20x+10y subject to 1.5x+3y =0

(i) Z = 20x + 10y x + 2y le 28, 3x + y le 24, x ge 2, x, y ge 0 (ii) Z = 7x + 10y 4x + 6y le 240, 6x + 3y le 240, x ge 10, x ge 0, y ge 0 (iii) Z = 22x + 44y subject to the constraints: x + y ge 3, 3x + 8y le 24, x - y ge 0, x, y ge 0 .

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5

Find the least value of 3x+4y for positive values of x and y, dubject to the condition x^(2)y^(3)=6 .

Find the least value of 3x+4y for positive values of x and y, dubject to the condition x^(2)y^(3)=6 .

Find the least value of 3x+4y for positive values of x and y, dubject to the condition x^(2)y^(3)=6 .

The image of the line (x-1)/(3)=(y-3)/(1)=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1)(x+3)/(3)=(y-5)/(1)=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/(5) (3) (x-3)/(3)=(y+5)/(1)=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/(5)