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A stone thrown vertically upwards rises S ft in t seconds where S =112t-16t ^(2) . The maximum height reached by the stone is

A missile is fired from the ground level rises x metres vertically upwards in t second, where x=100 t-25/2t^(2) . The maximum height reached is

A stone projected vertically upward moves according to the law s = 100t-16t^2 . The maximum height reached is

A missile is fired from the ground level rises x metre vertically upwards in t second, where x=100t-(25)/(2)t^(2) . The maximum height reached is

A stone thrown vertically upwards satisfies the equations s = 80t –16t^(2) . The time required to reach the maximum height is

A stone projected vertically upward with initial velocity of 112 feet per second moves according to the equation s=112t-16t^2 where s is the distance , in feet , from the ground , and t is time , in seconds. What is the maximum height reached by the stone ?

A particle is fired straight up from the ground to each a height of x feet in t seconds, where x (t) =128t-16t^(2) . (1) Compute the maximum height of the particle reached. (2) What is the velocity when the particle hits the ground ?

A stone is thrown in upward direction. Its equation is S=80 t-16 t^(2) . The time to attain maximum height is …………. second.