Plot the region in the first quadrant in which points are nearer to the origin than to the line `x=3.`

Consider a square with vertices at (1,1)(-1,1)(-1,-1)and(1,-1). Let S be the region consisting of all points inside the square which are nearer to the origin than to any edge. Sketch the region S and find its area.

Find the area of the region in the first quadrant enclosed by the x-axis, the line y=x and the circle x^2+y^2=32 .

Find the area of the region in the first quadrant enclosed by the x-axis,the line y=x and the circle x^(2)+y^(2)=32

Find the area of the region lying in the first quadrant bounded by the curve y^(2)=4x , X axis and the lines x=1, x=4 .

Find the area of the region in the first quadrant enclosed by the y-axis,the line y=x and the circle x^(2)+y^(2)=32, using integration.

Area of the region in the first quadrant exclosed by the X-axis, the line y=x and the circle x^(2)+y^(2)=32 is

Area of the region in the first quadrant exclosed by the X-axis, the line y=x and the circle x^(2)+y^(2)=32 is

Find the area of the region in the first quadrant enclosed by x-axis,the line x=sqrt(3)y and the circle x^(2)+y^(2)=4