Suggest a mechanism for the dehydration of `CH_3CHOHCH_3` that proceeds through a carbonium ion intermediate. Assign a cataltic role to the acid and keep in mind that the O in ROH is a basic site like O in `H_2O`.

Explanation

To suggest a mechanism for the dehydration of `CH3CHOHCH3` (isopropanol) that proceeds through a carbonium ion intermediate, we can follow these steps:

### Step-by-Step Solution:

1. **Protonation of Alcohol**:
- The first step involves the protonation of the hydroxyl group (-OH) of isopropanol (`CH3CHOHCH3`) by the acid (e.g., sulfuric acid, H2SO4). The oxygen atom in the -OH group acts as a base and accepts a proton (H+), forming an oxonium ion.
- Reaction:
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