The treatment of `C_2H_5Mgl` with water produces

Options

A. methane
B. ethane
C. ethanal
D. ethanol

Answer

To solve the problem of what the treatment of \( C_2H_5MgI \) with water produces, we can follow these steps:

### Step 1: Identify the compound
The compound \( C_2H_5MgI \) is known as a Grignard reagent. It is formed from ethyl halide (in this case, ethyl iodide) reacting with magnesium.

### Step 2: Understand the Grignard reagent
Grignard reagents have the general formula \( R-MgX \), where \( R \) is an alkyl or aryl group and \( X \) is a halogen. In this case, \( R \) is \( C_2H_5 \) (ethyl group) and \( X \) is \( I \) (iodine).

### Step 3: Reaction with water
When a Grignard reagent reacts with water, it undergoes hydrolysis. The Grignard reagent acts as a strong nucleophile and reacts with water (which can be considered as \( H-OH \)).

### Step 4: Write the reaction
The reaction can be represented as:
\[ C_2H_5MgI + H_2O \rightarrow C_2H_5OH + Mg(OH)I \]
In this reaction, the ethyl group \( C_2H_5 \) from the Grignard reagent combines with a hydroxyl group from water to form ethanol (\( C_2H_5OH \)). The magnesium iodide (\( Mg(OH)I \)) is formed as a byproduct.

### Step 5: Identify the product
From the reaction above, we can see that the main organic product formed is ethanol.

### Conclusion
The treatment of \( C_2H_5MgI \) with water produces ethanol.

### Final Answer
Ethanol

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