The treatment of `CH_3MgI` with water produces

Options

A. methane
B. ethane
C. ethanal
D. ethanol

Answer

To solve the question regarding the treatment of `CH₃MgI` (methylmagnesium iodide) with water, we can follow these steps:

### Step 1: Understand the Reactants
`CH₃MgI` is a Grignard reagent, which consists of a methyl group (`CH₃`) attached to a magnesium atom (`Mg`) that is also bonded to an iodine atom (`I`). Grignard reagents are known for their nucleophilic properties.

### Step 2: Identify the Reaction with Water
When `CH₃MgI` is treated with water, the water molecule can act as an acid, providing a proton (H⁺) for the reaction. The methyl group (`CH₃`) in `CH₃MgI` is negatively charged (due to the presence of the magnesium), making it a strong nucleophile.

### Step 3: Nucleophilic Attack
The negatively charged methyl group (`CH₃⁻`) will attack the hydrogen atom of the water molecule. This results in the formation of methane (`CH₄`) and a hydroxide ion (`OH⁻`).

### Step 4: Formation of Products
The reaction can be summarized as follows:
- `CH₃MgI + H₂O → CH₄ + Mg(OH)I`

In this reaction:
- Methane (`CH₄`) is released as a gas.
- A magnesium hydroxide iodide complex (`Mg(OH)I`) is formed.

### Final Answer
The treatment of `CH₃MgI` with water produces methane gas (`CH₄`) and magnesium hydroxide iodide (`Mg(OH)I`).

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