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Arrange the following in order of increa...

Arrange the following in order of increase/decrease in boiling point,
`underset(I)(CH_3CH_2CH_2CH_2CH_3),underset(II)((CH_3)_2CHCH_2CH_3),underset(III)((CH_3)_4C)`
Which of the folllowing is/are correct?

A

`I gt II gt III`

B

`II gt I gt III`

C

`III gt I gt II`

D

`III lt II lt I`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of boiling points for the given alkanes, we will analyze the three compounds based on their structure and the factors affecting boiling points. ### Given Compounds: 1. **(I)** Pentane: \( CH_3CH_2CH_2CH_2CH_3 \) (5 carbon straight chain) 2. **(II)** 2-Methylbutane: \( (CH_3)_2CHCH_2CH_3 \) (branched structure with 5 carbons) 3. **(III)** 2,2-Dimethylpropane: \( (CH_3)_4C \) (highly branched structure with 5 carbons) ### Step-by-Step Analysis: 1. **Identify the Structure and Surface Area**: - **Pentane (I)**: This is a straight-chain alkane with a larger surface area compared to the branched ones. - **2-Methylbutane (II)**: This is a branched alkane, which reduces the surface area compared to pentane. - **2,2-Dimethylpropane (III)**: This is the most branched structure, having the least surface area among the three. 2. **Understanding Boiling Point Trends**: - Boiling points of alkanes generally increase with increasing molecular weight and surface area due to stronger Van der Waals forces. - Branched alkanes tend to have lower boiling points than their straight-chain isomers because branching decreases the surface area available for intermolecular interactions. 3. **Comparing the Boiling Points**: - **Pentane (I)** will have the highest boiling point due to its straight-chain structure and larger surface area. - **2-Methylbutane (II)** will have a lower boiling point than pentane but higher than 2,2-dimethylpropane due to its moderate branching. - **2,2-Dimethylpropane (III)** will have the lowest boiling point because it is the most branched and has the smallest surface area. ### Conclusion: Based on the analysis, we can arrange the compounds in order of increasing boiling point as follows: - **Increasing Order**: \( (III) < (II) < (I) \) - **Decreasing Order**: \( (I) > (II) > (III) \) ### Final Answer: - Increasing Order: **(III) < (II) < (I)** - Decreasing Order: **(I) > (II) > (III)**
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