When ethyl alcohol is heated with conc `H_(2)SO_(4)` at 443K then the product formed is :

Options

A. `CH_(3)-CH_(2)-OSO_(3)H`
B. `(C_(2)H_(5))_(2)SO_(4)`
C. `C_(2)H_(4)`
D. `C_(2)H_(5)-O-C_(2)H_(5)`

Explanation

To solve the question, "When ethyl alcohol is heated with concentrated H₂SO₄ at 443K, what product is formed?", we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant in this reaction is ethyl alcohol, which has the molecular formula C₂H₅OH (or CH₃CH₂OH).

2. **Understand the Reaction Conditions**: The reaction is carried out with concentrated sulfuric acid (H₂SO₄) at a temperature of 443K. This temperature is significant because it indicates that the reaction will favor the formation of alkenes rather than ethers.

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