When diethyl ether is heated with an excess of `PCl_(5)`, it yields:

Options

A. ethyl choride
B. diethyl ether peroxide
C. ethanoly chloride
D. perchlorodiethyl ether

Explanation

To solve the problem of what happens when diethyl ether is heated with an excess of phosphorus pentachloride (PCl5), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Diethyl Ether**:
Diethyl ether has the chemical formula C2H5-O-C2H5. It consists of two ethyl groups (C2H5) connected by an oxygen atom.

2. **Reaction with PCl5**:
When diethyl ether is heated with PCl5, the lone pair of electrons on the oxygen atom in the ether can attack the phosphorus atom in PCl5. This leads to the formation of a complex.

3. **Formation of Alkyl Chlorides**:
As the reaction proceeds, one of the chlorine atoms from PCl5 is released as a chloride ion (Cl⁻). The ether molecule (C2H5-O-C2H5) forms a bond with PCl4, resulting in the formation of an intermediate compound.

4. **Cleavage of Ether**:
The chloride ion (Cl⁻) can then attack one of the carbon atoms of the ethyl group, leading to the cleavage of the ether bond. This results in the formation of ethyl chloride (C2H5Cl) and a phosphorous oxychloride (POCl3) byproduct.

5. **Final Products**:
The overall reaction yields two moles of ethyl chloride (C2H5Cl) and one mole of phosphorous oxychloride (POCl3).

### Conclusion:
When diethyl ether is heated with an excess of PCl5, it yields:
- **2 moles of ethyl chloride (C2H5Cl)**
- **1 mole of phosphorous oxychloride (POCl3)**

### Final Answer:
The main product is ethyl chloride (C2H5Cl).

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