`C_(6)H_(5)OH+ClCOCH_(3) overset("Aq. NaOH")rarr C_(6)H_(5)COOCH_(3)` is an example of

Options

A. Dow's reaction
B. Reimer-Tiemann reaction
C. Schotten-Baumann reaction
D. Kolbe's reaction

Answer

To solve the question `C_(6)H_(5)OH + ClCOCH_(3) overset("Aq. NaOH")rarr C_(6)H_(5)COOCH_(3)`, we need to analyze the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The first reactant is `C6H5OH`, which is phenol.
- The second reactant is `ClCOCH3`, which is acetyl chloride (an acyl halide).

2. **Understand the Role of Aqueous NaOH:**
- Aqueous NaOH acts as a base in this reaction. It deprotonates phenol to form phenoxide ion, which is a stronger nucleophile.

3. **Formation of Phenoxide Ion:**
- When phenol reacts with NaOH, it loses a proton (H+) to form the phenoxide ion:
\[ C6H5OH + NaOH \rightarrow C6H5O^{-}Na^{+} + H2O \]
- The phenoxide ion is now ready to react with the acyl halide.

4. **Nucleophilic Attack:**
- The phenoxide ion (C6H5O-) acts as a nucleophile and attacks the carbonyl carbon of acetyl chloride (ClCOCH3). This is a typical nucleophilic acyl substitution reaction.
- The reaction can be represented as:
\[ C6H5O^{-} + ClCOCH3 \rightarrow C6H5COOCH3 + Cl^{-} \]
- Here, the oxygen from the phenoxide ion forms a bond with the carbonyl carbon, and the chlorine leaves as a chloride ion.

5. **Formation of the Ester:**
- The product formed is `C6H5COOCH3`, which is an ester known as phenyl acetate.

### Conclusion:
The reaction `C_(6)H_(5)OH + ClCOCH_(3) overset("Aq. NaOH")rarr C_(6)H_(5)COOCH_(3)` is an example of **nucleophilic acyl substitution**, specifically the formation of an ester from phenol and an acyl chloride.