[(" iv ")quad x-3y-7=0],[3x-3y-15=0]

Which of the following pairs of linear equations has unique solution,no solution,or infinitely many solutions.In each there is unique solution ,find it by using cross multiplication method.(iv)3x-3y-7=0 3x-3y-15=0

Solve [2x+3y-7=0],[3x+2y-8=0]

solve for x and y 2x-3y+7=0 3x+4y-5=0

x - y - 5 =0, 3x + 5y - 15 = 0

Find the angles of the triangle whose sides are x+y-4=0, 2x+y-6=0, 5x+3y-15=0

" If the lines "5x-3y+15=0" and "5x+3y-15=0" forms a triangle with "X-" axis. Then the radius of circum circle is "

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then: