A body of mass 10 kg moving with speed of `3 ms ^(-1)` collides with another stationary body of mass 5 kg As a result, the two bodies stick togethre. The KE of composite mass will be

A mass of 20 kg moving with a speed of 10 m / s collides with another stationary mass of . 5kg As a result of the collision, the two masses stick together. The kinetic energy of the composite mass will be

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body A of mass 20 kg collides with another body B of mass 1 kg. then

A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. The lighter block comes to rest after collision. The loss in KE of the system is

A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. If the lighter block comes to rest after collision, then the speed of the heavier body is

A body of mass 2 kg moving with uniform velocity of 40 ms^(-1) collides with another body at rest . If two bodies move together with a velocity of 20 ms^(-1) . Find the mass of the other body .

A body of mass 10 kg and velocity 10 m/s collides with a stationary body of mass 5 kg . After collision both bodies stick to each other , velocity of the bodies after collision will be