If `plambda^4+qlambda^3+rlambda^2+slambda+t=|(lambda^2+3lambda,lambda-1,lambda+3),(lambda+1,2-lambda,lambda-4),(lambda-3,lambda+4,3lambda)|,` then value of t is

Let p lambda^4+qlambda^3+rlambda^2+slambda+t = |{:(lambda^2+3lambda,lambda-1,lambda-3),(lambda-1,-2lambda,lambda-4),(lambda-3,lambda+3," "3lambda):}| be an identity in lambda where p,q,r,s and t are constants. Then the value of t is

"Let "plambda^(4) + qlambda^(3) +rlambda^(2) + slambda +t =|{:(lambda^(2)+3lambda,lambda-1, lambda+3),(lambda+1, -2lambda, lambda-4),(lambda-3, lambda+4, 3lambda):}| be an identity in lambda , where p,q,r,s and t are constants. Then, the value of t is..... .

"Let "plambda^(4) + qlambda^(3) +rlambda^(2) + slambda +t =|{:(lambda^(2)+3lambda,lambda-1, lambda+3),(lambda+1, -2lambda, lambda-4),(lambda-3, lambda+4, 3lambda):}| be an identity in lambda , where p,q,r,s and t are constants. Then, the value of t is..... .

Let plambda^(4)+qlambda^(3)+rlambda^(2) + slambda+t= |{:(lambda^(2)+3lambda,,lambda-1,,lambda+3),(lambda+1 ,,-2lambda,,lambda-4),(lambda-3,,lambda+4,,3lambda):}| be an indentity in lambda p,q, r s and r are constants. Then find the value of t.

If plambda^4+qlambda^3+rlambda^2+slambda+t=|[lambda^2+3lambda, lambda-1, lambda+3] , [lambda^2+1, 2-lambda, lambda-3] , [lambda^2-3, lambda+4, 3lambda]| then t=

If plambda^4+qlambda^3+rlambda^2+slambda+t=|[lambda^2+3lambda, lambda-1, lambda+3] , [lambda^2+1, 2-lambda, lambda-3] , [lambda^2-3, lambda+4, 3lambda]| then t=

If plambda^4+qlambda^3+rlambda^2+slambda+t=|[lambda^2+3lambda, lambda-1, lambda+3] , [lambda^2+1, 2-lambda, lambda-3] , [lambda^2-3, lambda+4, 3lambda]| then t=

If plambda^4+qlambda^3+rlambda^2+slambda+t=|[lambda^2+3lambda, lambda-1, lambda+3] , [lambda^2+1, 2-lambda, lambda-3] , [lambda^2-3, lambda+4, 3lambda]| then t=

If plambda^4+qlambda^3+rlambda^2+slambda+t=|[lambda^2+3lambda, lambda-1, lambda+3] , [lambda^2+1, 2-lambda, lambda-3] , [lambda^2-3, lambda+4, 3lambda]| then t=

If plambda ^(4)+qlambda^(3)+rlambda ^(2)+ s lambda +t= |{:(lambda^(2)+3,lambda -1, lambda +3),(lambda^(2)+1,2-lambda ,lambda-3),(lambda^(2)-3,lambda+4,3lambda):}| then t is equal to : a)33 b)22 c)21 d)57