The area bounded by the curve `a^2y=x^2(x+a)` and the x-axis is `(a^2)/3s qdotu n i t s` (b) `(a^2)/4s qdotu n i t s` `(3a^2)/4s qdotu n i t s` (d) `(a^2)/(12)s qdotu n i t s`

Let f(x)=m in i mu m(x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is 7/3s qdotu n i t s 1/6s qdotu n i t s (11)/6s qdotu n i t s (d) 7/6s qdotu n i t s

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

The area bounded by the curve y^2=8x\ a n d\ x^2=8y is (16)/3s qdotu n i t s b. 3/(16)s qdotu n i t s c. (14)/3s qdotu n i t s d. 3/(14)s qdotu n i t s

The area bounded by the two branches of curve (y-x)^2=x^3 and the straight line x=1 is 1/5s qdotu n i t s (b) 3/5s qdotu n i t s 4/5s qdotu n i t s (d) 8/4s qdotu n i t s

The area enclosed between the curves y=(log)_e(x+e),x=(log)_e(1/y), and the x-axis is 2s qdotu n i t s (b) 1s qdotu n i t s 4s qdotu n i t s (d) none of these

The area bounded by the curve y^2=1-x and the lines y=(|x|)/x ,x=-1,a n dx=1/2i s 3/(sqrt(2))-(11)/6s qdotu n i t s (b) 3sqrt(2)-(11)/4s qdotu n i t s 6/(sqrt(2))-(11)/5s qdotu n i t s (d) none of these

The area of the closed figure bounded by x=-1,x=2,a n d y={-x^2+2,xlt=1 2x-1,x >1a n dt h ea b s c i s s aa xi si s (16)/3s qdotu n i t s (b) (10)/3s qdotu n i t s (13)/3s qdotu n i t s (d) 7/3s qdotu n i t s

Consider two curves C_1: y^2=4[sqrt(y)]x a n dC_2: x^2=4[sqrt(x)]y , where [.] denotes the greatest integer function. Then the area of region enclosed by these two curves within the square formed by the lines x=1,y=1,x=4,y=4 is 8/3s qdotu n i t s (b) (10)/3s qdotu n i t s (11)/3s qdotu n i t s (d) (11)/4s qdotu n i t s

Area bounded by y=sqrt(5-x^2)a n dy=|x-1| is: (A) (5pi-2)/3 s qdotu n i t s (B) (5pi-2)/4 s qdotu n i t s (C) (5pi)/4 s qdotu n i t s (D) none of these

The value of the parameter a such that the area bounded by y=a^2x^2+a x+1, coordinate axes, and the line x=1 attains its least value is equal to 1/4s qdotu n i t s (b) 1/2s qdotu n i t s 3/4s qdotu n i t s (d) -1s qdotu n i t s